A ferry makes an 80km trip down the river in 5 hours. The trip back against the current takes 8 hours. Fin the speed of the ferry and the current.
Let's create some variables to help: f - speed of the ferry c - speed of the current So, what's the total (or net) velocity when the ferry is moving with the current. Against the current?
f+c and f-c
OK. We know that, both ways, it traveled 80km. One way, it took 5 hours, the other way took 8. Do you know the equation for average speed?
D=RxT? Not sure..
Yeah, that's the one. Let's rearrange it a bit though: \[speed = \frac{distance}{time}\]
Using that, can you find the average velocity for each direction?
*average speed
80/5 and 80/8
Yup! Those simplify to 16 and 10. So, when the ferry is traveling with the current, the speed is 16 km/h, and when it's traveling against the current, the speed is 10 km/h. Using these numbers, and the equations you found earlier, can you set up a system of equations?
80=16f+c and 80=10f-c?
oh wait nevermind
Im not sure haha
Remember, the first equation (f+c) is the total speed when the ferry is travelling with the current. f-c is when it's travelling against. This leaves us with: f + c = 16 f - c = 10
ohh alright, then we use elimination?
Whichever method is easiest for you.
Ok awesome, thanks so much :) you were a big help
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