A & D???Which inequality will have a shaded area above its graph? 2x − y ≥ 4 4x + 3y < 6 x − 9y ≤ 1 x − 3y > 4
put in y = mx + b form A. 2x - y >= 4 -y >= -2x + 4 --- multiply by -1 to make y positive...and change inequality sign y <= 2x - 4 < less then means shading below the line....this is not the correct answer D. x - 3y > 4 -3y > -x + 4 -- divide by -3...change sign y < x - 4/3 < less then....not correct so it is not A or D try doing the same with the other answer choices and see what you get
just remember that when putting in y = mx + b form, when dividing/multiplying by a negative, it changes the inequality sign
y>x/9-1/9
@dan815
I don't get why I had to put it into y=mx+b form
@Hero
|dw:1430869493327:dw|
it means, if x =1, y =1 if x =2, y =2, ok?
So I have to put it into y=mx+b?
|dw:1430869544638:dw|
I get that
that means , y > x (GREATER THAN X)
I also get that, But A & D are greater
hence, all you have to do is isolate y
and if they ask you ABOVE, that is your y must > the other
Ohhhhhhhhhhhh.
I didn't know it had to be above to y=x line, and y>____
for A) \(2x-4\geq y\)
your y is LESSER, it is not GREATER
I get how to isolate
I understand now. Thanks!
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