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Physics 17 Online
OpenStudy (anonymous):

a diffration grating has 250lines/cm. the 4th order image is formed at an angle of 4.00. what is the wavelength ?

OpenStudy (anonymous):

the formula to use is wavelenth=dsin/n , but i am doing somthing wrong i thik

OpenStudy (anonymous):

do we do simthing to 250?

OpenStudy (anonymous):

We have 250 lines per cm. How many cm per line?

OpenStudy (anonymous):

what u mean

OpenStudy (anonymous):

d is the distance between lines. If you have 250 lines per centimeter, what is the distance between the lines?

OpenStudy (anonymous):

1/250?

OpenStudy (anonymous):

Yep. Try using that for d, and you should be good to go!

OpenStudy (anonymous):

i did that but still

OpenStudy (anonymous):

is n 4 ?

OpenStudy (anonymous):

If they are using the standard notation, yeah. The center fringe is the 0th order, next out is 1st, etc.

OpenStudy (anonymous):

the a answer is 698nm

OpenStudy (anonymous):

what u did was 1/250*sin4/4

OpenStudy (anonymous):

Remember, 1/250 is in cm.

OpenStudy (anonymous):

so first its 1/250 * 1000?

OpenStudy (anonymous):

what do we change it to ?

OpenStudy (anonymous):

1/250 * 10^(-2) m

OpenStudy (anonymous):

i still dont get 698nm

OpenStudy (anonymous):

Strange. I do. Make sure your calculator is working with degrees (not radians) \[\frac{1}{250} \times \sin(4^o) \times \frac{1}{4}\]

OpenStudy (anonymous):

You should end up with 6.97565*10^(-07) m, which is (rounded to) 678 nm

OpenStudy (anonymous):

oh okey i got that to before and i thought i was wrong

OpenStudy (anonymous):

wait so how does that work ? how do u just round it ?

OpenStudy (anonymous):

Ah \[6.97565\times 10^{-7} = 697.565\times 10^{-9}\] \[10^{-9}\textrm{m} = 1\textrm{nm}\]

OpenStudy (anonymous):

so would it have been easier if i had converted 250cm to nm first?

OpenStudy (anonymous):

just put 10^-9 after 250

OpenStudy (anonymous):

1/250 cm to nanometers would have worked, yeah. "Easier" depends on how you look at it. I prefer to take everything to base units for situations like this.

OpenStudy (anonymous):

No, not 10^(-9) 1/250 cm = 1/250 * 10^7 nm

OpenStudy (anonymous):

You should look up a chart on metric conversions. Keep that around until you're more familiar with using it.

OpenStudy (anonymous):

i have a chart

OpenStudy (anonymous):

it says -9

OpenStudy (anonymous):

10^(-9)m = nm or 10^9 nm = m nm are smaller, so there will be more of them.

OpenStudy (anonymous):

can u help me with other questions

OpenStudy (anonymous):

Sure

OpenStudy (anonymous):

hold on

OpenStudy (anonymous):

a photon with a wavelenth of 950nm has what frequecy

OpenStudy (anonymous):

We know that \[c = \lambda \nu \] where c is the speed of light, lambda (the kind of h looking thing) is the wavelength, and nu (the v looking thing) is the frequency. We know the speed of light is 3.0*10^8 m/s, so using the frequency, we can find the wavelength (be careful of units!!!)

OpenStudy (anonymous):

the next question is the same but this time it says whats the energy ?

OpenStudy (anonymous):

For a photon \[E = h \nu\] where h is Planck's constant

OpenStudy (anonymous):

i have e=pc on my sheet

OpenStudy (anonymous):

wait in the first question it was asked frequency their is no f in the equation u gave me

OpenStudy (anonymous):

\[p = \frac{h}{\lambda} = \frac{h\nu}{c}\] So \[E = pc = \frac{h\nu}{c}c = h\nu\]

OpenStudy (anonymous):

What you call c, I'm calling nu. I'll switch from here on out. \[f = \nu\]

OpenStudy (anonymous):

err, f. Not c.

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

wait u mean no v but f

OpenStudy (anonymous):

c is a constant and we need it

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