Question

Calculus. Medal.

Answer 1

\[10 \cos x-4 \sin x\]

Answer 2

Exactly what should we do here?

Answer 3

I don't think we can simplify it more.

Answer 4

well I know it's \[10 d/dx[\cos x] - 4 d/dx[sinx]\right?\]

Answer 5

the latex has to be between delimiters
```
\[ ....code.... \]
```

Answer 6

\right is actually a command so its not good to right inside of it

Answer 7

```
\[10 \frac{d}{dx}[\cos x] - 4 \frac{d}{dx}[sinx] \]
```
\[10 \frac{d}{dx}[\cos x] - 4 \frac{d}{dx}[sinx] \]

Answer 8

@CimberJackson Well, you are right about\[\dfrac{\mathbb d}{\mathbb d x}(10\cos x-4\sin x) = 10\cdot\dfrac{\mathbb d}{\mathbb d x}(\cos x)-4\cdot\dfrac{\mathbb d}{\mathbb d x}(\sin x)\]

Answer 9

left and right are for brackets
```
\[\left( 10 \frac{d}{dx}[\cos x] - 4 \frac{d}{dx}[sinx] \right)\]
```

\[\left( 10 \frac{d}{dx}[\cos x] - 4 \frac{d}{dx}[sinx] \right)\]

Answer 10

so now what?

Answer 11

Well, just take derivative of sin x and cos x.

Do you remember what these derivatives are?

Answer 12

umm cos is sinxcosx?

Answer 13

No. You are thinking of sec x.

Answer 14

Do you have note or table you can check?

Answer 15

f(x) cos x=-sin x
f(x) sin x = cosx?

Answer 16

Yeah d/dx cos x = -sinx

and d/dx sin x = cos x

Answer 17

Yess :D

Answer 18

so now we have -10 sinx - 4cosx.. now what

Answer 19

We should be done here.

Answer 20

\[\dfrac{\mathbb d}{\mathbb d x}(10\cos x-4\sin x) = \boxed{-10\sin x-4\cos x}\]

Answer 21

We cannot simplify it more, so yeah.

Answer 22

Yes it's right! :) thank you