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Chemistry 7 Online
OpenStudy (anonymous):

***WILL FAN AND MEDAL*** Can somebody help me with my lab?

OpenStudy (anonymous):

OpenStudy (anonymous):

\(\Huge\bigstar\color{DarkViolet}{^Can~^Some_1~^Help~^Me?}\bigstar\)

OpenStudy (anonymous):

\[\Huge\bigstar\color{DarkViolet}{^Sorry~^No~^Time!}\bigstar\]

OpenStudy (aaronq):

we can work through it together. What have you done so far?

OpenStudy (anonymous):

Ugh nothing No clue what to do :p

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

first you need to fill that table. to find the energy you multiply the mass of the water (in this case because the density is assumed to be 1 g/mL, 1000 mL = 1000 g), times the specific heat capacity, times the change in temperature. The change in temperature is the difference between the final and the inital temps. \(\huge \Delta T=T_f-T_i\)

OpenStudy (anonymous):

ok um how do I do that exactly? I am so confused :p

OpenStudy (aaronq):

have you read the paragraph? it's all given there

OpenStudy (anonymous):

yah but im still sooooooooo confused ugh... :p I'm sorry

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

read the paragraph you need mass of water (which is the volume of water) specific heat capacity of water change in temperature for the water (increase or decrease) report these back

OpenStudy (anonymous):

Heat capacity would be 4.18? right?

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

yes

OpenStudy (anonymous):

Okay now what?

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

you need: mass of water (which is the volume of water) specific heat capacity of water \(\checkmark\) change in temperature for the water (increase or decrease)

OpenStudy (anonymous):

1,000 mL's 23.70

OpenStudy (anonymous):

Looks good so far.

OpenStudy (anonymous):

Thanks :D

OpenStudy (anonymous):

@aaronq but thnx @Ajohnson2199

OpenStudy (aaronq):

okay, now follow the formula provided, \(q=m*C*\Delta T\) multiply these three values together, it will give you the heat, q.

OpenStudy (anonymous):

OK :) What about after that?

OpenStudy (anonymous):

What are you trying to look for now?

OpenStudy (aaronq):

Now for the second part fo the same question, you divide the heat, q, by the mass of sodium hydroxide used.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

After that ? @aaronq

OpenStudy (aaronq):

so the table in 2. follows the exact same concept as the first. identify the mass of water used, multiply it by the heat capacity and the change in temperature. Note that this occurs twice, once for the chips and once for the tomatoes - each has a difference change in temperature,

OpenStudy (anonymous):

Okay Im confused once again 0_o

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

it's the same thing as in the first question. multiply the mass of the water used by specific heat capacity of water and the change in temperature to find the heat, q

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

And after that? @aaronq

OpenStudy (aaronq):

Convert the heat, q, from Joules to kilojoules. you do this by dividing the heat by 1000 because 1000 J= 1 kJ Then you divide by heat by the mass for each substance burned.

OpenStudy (anonymous):

ok Thanks :D

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

no problem!

OpenStudy (anonymous):

XD

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