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Find the length of the curve given parametrically by x = cos^3 (θ) , y = sin^3 (θ) between θ = 0 and θ = π .
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hello
\[\int\limits_{0}^{\pi} \sqrt{(\frac{dx}{d \theta})^2+(\frac{dy}{d \theta})^2} d \theta\]
that should be the integral representation of the length of the parametric curve x=x(theta) and y=y(theta) where theta is in [0,pi]
Can you differentiate both of your equations w.r.t to theta?
differentiating x=cos^3 (theta) would give 3cos^2 (theta)* sin(theta) differentiating y=sin^3 (theta) would give 3sin^2(theta) * -cos (theta)
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the first term is - , the second term is + . However, still have 4 more steps, 1) square them 2) add them 3)square root them 4) integrate them.
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