Question

Chef Imelda can do something unique. Using a secret process, she can bake a nearly perfectly spherical pie consisting of a chicken filling inside a thick crust. The radius of the whole pie is 19 cm, and the radius of the filling is 16 cm. What is the volume of the crust alone, to the nearest tenth of a unit? Use p˜ 3.14.


https://nnds-li.brainhoney.com/Resource/19791663,8AD/Assets/assessmentimages/lesson7_qu9.gif
110.0 cm3
11,564.8 cm3
11,567.8 cm3
113.0 cm3
@amistre64

Answer 1

@Michele_Laino

Answer 2

@welshfella

Answer 3

The anwer i a

Answer 4

how did you get a

Answer 5

oops, sorry I have made an error

Answer 6

ok

Answer 7

we have to compute the volume of the space enclòosed between the two speres, namely the 16 cm radius sphere, and the 19 cm radius sphere.
Now the volume V of a sphere whose radius is R, is given by the subsequent formula:
\[V = \frac{{4\pi }}{3}{R^3}\]
so the requested volume is:
\[\Large \begin{gathered}
V = \frac{{4\pi }}{3}R_2^3 - \frac{{4\pi }}{3}R_1^3 = \frac{{4\pi }}{3}\left( {R_2^3 - R_1^3} \right) = \hfill \\
\hfill \\
= \frac{{4\pi }}{3}\left( {{{19}^3} - {{16}^3}} \right) = ...? \hfill \\
\end{gathered} \]

Answer 8

4.1866 (6,859 - 4,096)

Answer 9

sorry for my grammar mistakes

Answer 10

ok! so, what is the final result?

Answer 11

iots not a sphere is it

Answer 12

your pie is perfectly spherical as I can read from the text of your question

Answer 13

11,567.5758

Answer 14

that's right! I got 11567,76, so we chan round off that result to 11,567.8 cm^3

Answer 15

ok thanks

Answer 16

thanks!