Question

Help finding an integral.

Answer 1

\[\int\limits_{1}^{4} \frac{ 3^\sqrt{x} }{ \sqrt{x} }\]

Answer 2

let u=sqrt(x)

Answer 3

\[2 \int\limits_{a}^{b}3^\sqrt{x} \frac{1}{2\sqrt{x}} dx\]
you should see the derivative of that exponent in the problem :)

Answer 4

Oh so from there it becomes \[2 \int\limits_{1}^{2} u du\]

Answer 5

well what happen to your base 3 thingy?

Answer 6

woops i mean 3^u

Answer 7

\[2 \int\limits_1^2 3^u du\]

Answer 8

yep that!

Answer 9

And when we take the integral of a base raised to a power it becomes...

Answer 10

3u over ln3

Answer 11

Alright i got it it's 12 over ln3 thanks for the help.