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Mathematics 8 Online
OpenStudy (anonymous):

medal and fan

OpenStudy (anonymous):

http://openstudy.com/code-of-conduct

OpenStudy (bloomlocke367):

it would be a lot easier if you posted one question at a time, but I'll try

OpenStudy (anonymous):

okay hold on please

OpenStudy (bloomlocke367):

okay

OpenStudy (anonymous):

question 1 Two lines, A and B, are represented by the equations given below: Line A: 2x + 2y = 8 Line B: x + y = 4 Which statement is true about the solution to the set of equations? It is (8, 4). It is (4, 8). There is no solution. There are infinitely many solutions.

OpenStudy (anonymous):

is that better?

OpenStudy (anonymous):

OpenStudy (bloomlocke367):

yes :)

OpenStudy (bloomlocke367):

okay, I know there's an easier way to solve it, but I've always been better with substitution. Do you know what that is?

OpenStudy (anonymous):

it doesn't say

OpenStudy (bloomlocke367):

okay, well we can solve the second equation for y, so it would be y=4-x. you then would plug that in for y in the first equation and you'd have \(2x+2(4-x)=8\). do you see what I did?

OpenStudy (anonymous):

sort of

OpenStudy (bloomlocke367):

what don't you get?

OpenStudy (anonymous):

I don't know how to to do this very well so it is confusing to me how you get from y=4-x too 2x+2(4−x)=8

OpenStudy (anonymous):

are you still there

OpenStudy (bloomlocke367):

okay, you know how it was \(2x+2\color{red}y=8\). well, the other equations was \(\color{red}{y=4-x}\). so you plug it in for y.. and you get \(2x+2\color{red}{(4-x)}=8\)

OpenStudy (bloomlocke367):

does that make more sense?

OpenStudy (anonymous):

yes!

OpenStudy (bloomlocke367):

okay. now just solve for x, do you know how?

OpenStudy (anonymous):

not really

OpenStudy (bloomlocke367):

okay, you're going to want to first use the distributive property.. do you know how to do that? when you have \(2(4-x)\) you distribute the 2 to each of the terms. so you need to do \(2\times4\) and \(2\times-x\)

OpenStudy (anonymous):

2x4=8 2x2=4

OpenStudy (bloomlocke367):

why'd you do \(2\times2\)?

OpenStudy (anonymous):

oh sorry they cancel

OpenStudy (anonymous):

is that right

OpenStudy (anonymous):

hello

OpenStudy (bloomlocke367):

I'm here.

OpenStudy (bloomlocke367):

I'm still confused as to why you did 2*2..

OpenStudy (anonymous):

k

OpenStudy (anonymous):

i thought it was just multiplying but then i remembered that you have to cancel

OpenStudy (anonymous):

one of them

OpenStudy (bloomlocke367):

after you distribute you should have \(2x+8-2x=8\)

OpenStudy (anonymous):

oaky

OpenStudy (anonymous):

okay

OpenStudy (bloomlocke367):

now can you solve that?

OpenStudy (anonymous):

how

OpenStudy (anonymous):

im really sorry i really have no idea how to do this

OpenStudy (bloomlocke367):

okay, well the first thing to do is combine like terms. what's \(2x-2x\)?

OpenStudy (anonymous):

0 ?

OpenStudy (bloomlocke367):

yes, but for now, we're going to say \(0x\) so we don't get confused. and what's \(8-8\)?

OpenStudy (anonymous):

0

OpenStudy (bloomlocke367):

yes, so you have \(0=0\) correct?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

so no solution

OpenStudy (bloomlocke367):

no, no solution would be if you had an answer that's undefined or something that was untrue, like 2=6

OpenStudy (anonymous):

oh okay

OpenStudy (bloomlocke367):

so do you know what it is now?

OpenStudy (anonymous):

infinite

OpenStudy (bloomlocke367):

Yep!

OpenStudy (anonymous):

yeah!!! woooooh!!

OpenStudy (anonymous):

can you help me with a few more please ☺

OpenStudy (bloomlocke367):

I'll try my best c: just open a new question

OpenStudy (anonymous):

okay

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