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A sample of compressed methane has a volume of 648 mL at a pressure of 503 kPa. To what pressure would the methane have to be compressed in order to have a volume of 216 mL? I will Give you Medals
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sounds like a problem of Boyle's Law
Required equation is p1v1=p2v2
Given p1=503kpa v1=648mL p2=? v2=216mL
Why do you assume T_1 = T_2 ? @shamim
Because temperature is not given
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So i assumed temperature is constant
Ok.
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