Question

Carmelo bought an electric guitar for $240.00 during the yearly sale at Strings Music Store. He purchased the guitar for $75.00 less than one third of its original price. Choose the equation you would use to find the original price, x, of the guitar.

Answer 1

A. http://diagnostic.achievementseries.com/cdn//1/_graphics_math_14157f/3afe916b-4b85-44a9-a698-81329be92159.gif
B. http://diagnostic.achievementseries.com/cdn//1/_graphics_math_14157g/aa52ebc0-a982-4f93-b592-69ac3902adf0.gif
C. http://diagnostic.achievementseries.com/cdn//1/_graphics_math_14157e/8e691852-4fb4-4cf8-b265-12dbd4b6a5e7.gif
D. http://diagnostic.achievementseries.com/cdn//1/_graphics_math_14157a/8dbafc4c-38cd-486d-90c1-0397db5331c1.gif

Answer 2

@jackmullen55 @Jaynator495

Answer 3

Hulk Doesnt Do Math x_x

Answer 4

awww

Answer 5

:( ok

Answer 6

@Michele_Laino

Answer 7

My question... how in the heck are you 70ss over night? LOL

Answer 8

Hint:
If I call with x the original price of the guitar, then one third of the original price is:
x/3
and $75 less than one third of the original price is :
x/3 - 75

Answer 9

Just yesterday i was barfing rainbows on you being your new... next thing i know your already grown up LOL

Answer 10

the answer is C right @Michele_Laino

Answer 11

that's right!

Answer 12

can you help me with more and thanx

Answer 13

ok!

Answer 14

thanx

Answer 15

Factor completely.

42 + 51x - 18x²


A. 6(3x + 1)(7 - x)
B. (3x - 7)(2x - 2)
C. 3(2 + 3x)(7 - 2x)
D. 3(3x - 7)(2x - 2)

Answer 16

here we have to find the roots of the polynomial:
\[18{x^2} - 51x - 42 = 0\]

Answer 17

ok

Answer 18

18^2=324

Answer 19

no, we have to apply this formula:
\[\Large x = \frac{{ - b \pm \sqrt {{b^2} - 4 \times a \times c} }}{{2 \times a}}\]
where a= 18, b=-51, and c= -42

Answer 20

\[x=\frac{ -51\pm \sqrt{-51^{2}- 4\times18\times-42} }{ 2*18 }\]

Answer 21

is that right

Answer 22

yes!

\[x = \frac{{51 \pm \sqrt {{{51}^2} - \left( {4 \times 18 \times - 42} \right)} }}{{2 \times 18}}\]

Answer 23

now, we have:
\[\Large \begin{gathered}
x = \frac{{51 \pm \sqrt {{{51}^2} - \left( {4 \times 18 \times - 42} \right)} }}{{2 \times 18}} = \hfill \\
\hfill \\
= \frac{{51 \pm \sqrt {2601 + 3024} }}{{36}} = ...? \hfill \\
\end{gathered} \]

Answer 24

\[=\frac{51\pm5625 }{ 36 }\]

Answer 25

I got this:
\[\begin{gathered}
\frac{{51 \pm \sqrt {2601 + 3024} }}{{36}} = \frac{{51 \pm \sqrt {5625} }}{{36}} = \hfill \\
\hfill \\
= \frac{{51 \pm 75}}{{36}}...? \hfill \\
\end{gathered} \]

Answer 26

ok so wat kn

Answer 27

we have the subsequent roots:
\[\Large \begin{gathered}
{x_1} = \frac{{51 + 75}}{{36}} = \frac{{126}}{{36}} = \frac{7}{2} \hfill \\
\hfill \\
{x_2} = \frac{{51 - 75}}{{36}} = - \frac{{24}}{{36}} = - \frac{2}{3} \hfill \\
\end{gathered} \]

Answer 28

I came back and realized it was a different person who started yesterday... my bad x'D

Answer 29

is the answer c @Michele_Laino cuz i think so

Answer 30

in ordert o find the answer you have to do this computation:
\[\Large \begin{gathered}
- 18\left( {x - \frac{7}{2}} \right) \times \left( {x + - \frac{2}{3}} \right) = \hfill \\
\hfill \\
= - 3 \times 2\left( {x - \frac{7}{2}} \right) \times 3 \times \left( {x + \frac{2}{3}} \right) = ... \hfill \\
\end{gathered} \]

Answer 31

o shot i took to long on this question and it loged me out so nvm

Answer 32

Sorry, I have made a typo, here is the right step:
\[\Large \begin{gathered}
- 18\left( {x - \frac{7}{2}} \right) \times \left( {x + \frac{2}{3}} \right) = \hfill \\
\hfill \\
= - 3 \times 2\left( {x - \frac{7}{2}} \right) \times 3 \times \left( {x + \frac{2}{3}} \right) = ... \hfill \\
\end{gathered} \]

Answer 33

ur ok

Answer 34

yes!

Answer 35

hint:
you have to multiply the factor 2 by the first parentheses, and then you have to multiply the factor 3 by the second parentheses

Answer 36

ok thanx ur a big help

Answer 37

you should get this:
\[\Large \begin{gathered}
- 18\left( {x - \frac{7}{2}} \right) \times \left( {x + \frac{2}{3}} \right) = \hfill \\
\hfill \\
= - 3 \times 2\left( {x - \frac{7}{2}} \right) \times 3 \times \left( {x + \frac{2}{3}} \right) = \hfill \\
\hfill \\
= - 3 \times \left( {2x - 7} \right) \times \left( {3x + 2} \right)... \hfill \\
\end{gathered} \]