Question

Who here can help me with finding the equilibrium temperature

Answer 1

what is the equilibrium of two masses both weigh 2 kg initial temperature of mass A was 100°C thermal equilibrium temp was 50°C Mass b initial temp 0°C and thermal equilibrium was 50°C.

What is the equilibrium of the two masses does this seem reasonable

Answer 2

i spose it depends on their specific heat properties

Answer 3

\[c_1m_1\triangle t_1+c_2m_2\triangle t_2=0\]
mass equal, change in tems seem to be equal but oppposite

Answer 4

havent been that good in physics tho so this is just what i recall from it

Answer 5

What do you mean by there specific heat properties?

Answer 6

each substance has a way in which it mitigates its transfer of heat, that value is known is its specific heat index

http://www.physics.louisville.edu/cldavis/phys298/notes/heat_thermeq.html

Answer 7

if they are the same substance, say water

50g of 99 degree water added to 60g of 23 degree water is at equilibrium when

50(99-d) = 60(23+d)

what is the temperature of the combined water?

Answer 8

the two masses are copper and a copper rod is used to transfer the heat from one copper mass to the other

Answer 9

then id assume, im no expert mind you, that the specific heat index for copper is the same for both masses

Answer 10

100-50 = 0 + 50, for a change in temp of 50degrees

but im not sure what it is you are asking at this point

Answer 11

they should even out at 50 degrees

Answer 12

yeah this thing is confusing me that's why am asking

Answer 13

the questions is What is the equilibrium temperature of the two masses

Answer 14

and those two masses are copper cubes both weighting 2 kg

Answer 15

50 degrees ....

Answer 16

heat transfers from the hot to the cold until there is no more heat difference between them. when no heat moves between them they are at equilibrium

Answer 17

initial temperature of mass A was 100°C thermal equilibrium temp was 50°C Mass b initial temp 0°C and thermal equilibrium was 50°C

Answer 18

so the equilibrium temperature of the two masses is 5o?

Answer 19

100 losses degrees: 100 - d

0 adds degrees, its taking from the other one: 0 + d

both of these equal when d = 50, and it just so happens that 100-50 - 50; and 0+50 = 50

so at 50 degress there is no more transfer of heat

Answer 20

okay understandable. My next questions does it seem reasonable

Answer 21

we would expect equal substances to impart equally yes

Answer 22

Can you also help me with something what if the initial temperature of mass b was not 0 can you show me how i would solve it with the equation you gave?

Answer 23

instead of 0 being the intial temp, use the stated intial temp

Answer 24

spose one started at 72 degrees, and the other at 41 all other htings being the same

Answer 25

72 - d = 41 + d

what is d? and therefore what is the equilibrium?

Answer 26

D equals 31

Answer 27

ive got major lag on my end ....

Answer 28

72 - d = 41 + d

31 = 2d

d = 31/2 this is our change in temperature

so the equilibrium temp is: 72-d, or just the same 41+d

Answer 29

is it 31 divided by 2?

Answer 30

@amistre64

Answer 31

@amistre64