who can solve this Copper;
Q= 1kgX387X(30.74-100)=
Aluminum;
Q= 1kgX899X(30.82-0)=

Question

who can solve this   Copper;
Q= 1kgX387X(30.74-100)=   
Aluminum;
Q= 1kgX899X(30.82-0)=

anonymous · Answer

@amistre64

amistre64 · Answer

what defines a soltuoin?

amistre64 · Answer

why -100 and -0?

anonymous · Answer

Mass A intitial temp 100°C thermal equilibrium temp 30.74°C mass 1 kg made of copper
Mass B initial temp 0°C thermal temp 30.82°C mass 1 kg made of aluminum

anonymous · Answer

@amistre64 
Q= energy transfer
M= mass of substance 
C= specific heat capacity 
Delta T= change in temperature
 
Copper;
Q= 1kgX387X(30.74-100)= 

Aluminum;
Q= 1kgX899X(30.82-0)=

anonymous · Answer

that's the answer to your why -100 and -0?

amistre64 · Answer

1kg  899  (30.82 - d)  <-- starts out at 30.82, and loses heat

1kg   387   (30.74 + d)  <-- start out as 30.74 and gains heat

899(30.82 - d) = 387(30.74 +d)

solve for d to determine what the equilibrium temp needs to be.

100 and 0 make no sense at the start

amistre64 · Answer

unless im just not reading the post correctly ...

amistre64 · Answer

we start at 100 and 0?  why do you have 4 different temps floating about?

amistre64 · Answer

if we start out as 100 and 0,  then they tend to equilize about 30.09,  but youve posted different setups and it shard to make any sense of it