Simplify (1-cosΘ)(1+cosΘ) / (1-sinΘ)/(1+sinΘ)?

Question

freckles · Answer

$$\frac{(1-\cos(\theta))(1+\cos(\theta))}{\frac{1-\sin(\theta)}{1+\sin(\theta)}} \text{ or } \frac{\frac{(1-\cos(\theta))(1+\cos(\theta))}{1-\sin(\theta)}}{1+\sin(\theta)}$$

jdoe0001 · Answer

$\bf \large \cfrac{\frac{1-cos(\theta)}{1+cos(\theta)}}{\frac{1-sin(\theta)}{1+sin(\theta)}} ?$

freckles · Answer

$$\frac{a}{\frac{b}{c}}=a \cdot \frac{c}{b} \text{ if the first one } \ \frac{\frac{a}{b}}{c}=\frac{a}{b} \cdot \frac{1}{c} \text{ if the second one }$$

jdoe0001 · Answer

or $\bf \cfrac{(1-cos(\theta)(1+cos(\theta)}{\frac{1-sin(\theta)}{1+sin(\theta)}} ?$

anonymous · Answer

a) sin^2Θ
b) cos^2Θ
c) tan^2Θ
d) cosΘ/sinΘ

anonymous · Answer

@freckles which one do you think it is?

freckles · Answer

I don't even know what the problem is

freckles · Answer

joe and I both asked you and you answered neither one of us

anonymous · Answer

@freckles what does a, b, and c stand for?

anonymous · Answer

I think it's d...am I right?

jdoe0001 · Answer

$\bf \cfrac{(1-cos(\theta)(1+cos(\theta)}{\frac{1-sin(\theta)}{1+sin(\theta)}} $

is what you have right?

jdoe0001 · Answer

well... I don' think we even know what the expression is

jdoe0001 · Answer

is it $\bf \large \cfrac{\frac{1-cos(\theta)}{1+cos(\theta)}}{\frac{1-sin(\theta)}{1+sin(\theta)}} ?$

anonymous · Answer

yes it is

anonymous · Answer

@jdoe0001 so is my answer right?

jdoe0001 · Answer

wel... haven't seen any work done though

jdoe0001 · Answer

I don't see it simplyfing per se

so.. got any postings of what you did to get that?

you can always attach a file using the [Attach File] button, so we can see it

freckles · Answer

I kinda would like to know what expression you were given because the expression you told joe you were given doesn't match any of the choices given

since you haven't been able to tell us what the expression was, a picture of it would be nice

jdoe0001 · Answer

hmmm

anonymous · Answer

never mind, I got it. thank you

jdoe0001 · Answer

from what you showed above, it sounds that what you have is $\bf \cfrac{(1-cos(\theta)(1+cos(\theta)}{\frac{1-sin(\theta)}{1+sin(\theta)}}$

as opposed to what you said "yes" to

jdoe0001 · Answer

kinda hard to grab a slippery goose =)