Question

Problem 54/120

A committee of four is chosen randomly from a group of six males and eight females. What is the probability that the committee includes either all males or all females? (Round your answer to four decimal places.)

Answer 1

The probability of all males is given by:
\[\large P(4\ males)=\frac{6C4}{14C4}\]
The probability of all females is given by:
\[\large P(4\ females)=\frac{8C4}{14C4}\]
The events '4 males' and '4 females' are mutually exclusive. Therefore
P(4 males or 4 females) = P(4 males) + P(4 females)

Answer 2

@kropot72 Thank you !!! your a life saver !!!

Answer 3

You're welcome :)