Question

If the distance between two objects is increased to four times the original distance, how will that increase change the force of attraction between the objects?

Answer 1

Gravitational attraction force is inversely proportional to the r^2

Answer 2

Here r is the distance between 2 objects

Answer 3

If r becomes 4r, the (4r)^2=16r^2

Answer 4

So gravitational attraction force will b decrease by 16 times

Answer 5

Response plz!

Answer 6

Hint:
before to increase the distance, the force is:
\[\Large F = K\frac{{{M_1}{M_2}}}{{{d^2}}}\]
after that the distance has been increased, we can write:
\[\Large {F_1} = K\frac{{{M_1}{M_2}}}{{{{\left( {4d} \right)}^2}}} = K\frac{{{M_1}{M_2}}}{{16{d^2}}} = \frac{F}{{16}}\]

Answer 7

where, as usually, K=6.67*10^(-11) N*m^2*Kg^2