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There are ____ atoms in 80 g of copper. Help
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For this question you need two steps. First find the moles, \(\sf moles=\dfrac{mass}{Molar~mass}\) then multiply by avogadro's number, \(\sf \#~atoms=moles*avogadro's~number \)
The Avogadro number is 6.022x10^23
Right
yes
First convert the 80 grams of copper into moles of copper by multiplying by ( 1 mole / 63.55 g). Then use Avogadra's number = 6.022 X 10 ^23 to convert from moles Cu to atoms Cu. So basically: (80 g Cu) x (1 mol Cu / 63.55 g Cu) x (6.022 x 10 ^23 atoms / 1 mol Cu). The first answer is 7.58 x 10 ^ 23 atoms Copper.
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