Simplify.\[\Large\tt\frac{8}{5b+2}+\frac{10}{3b-4}\]
I already know that the denominator would be (5b + 2)(3b - 4). I just need help with the numerator.
wait i'll solve
2(37b−6)(3b−4)(5b+2)
Did you mean: \[\frac{2(37-6)}{(3b-4)(5b+2)}\]
yea
How did you get that answer? :)
I think I know, but I am not sure. Let me finish what I was doing offline and see if I get the same answer.
ok
Can you show me the steps you took to get your answer? @MGLMystiicz
@rational Can you help me? :)
\[\tt\frac{8}{5b+2}+\frac{10}{3b-4}\] You have two fractions with different denominators, so you cannot combine them directly.
Get common denominator first
The common denominator is (5b + 2)(3b - 4).
multiply top and bottom of first fraction by 3b-4 multiply top and bottom of second fraction by 5b+2 \[\tt\frac{8(3b-4)}{(5b+2)(3b-4)}+\frac{10(5b+2)}{(3b-4)(5b+2)}\]
Now that the bottoms of both fractions are same, you may add the numerators and put the common denominator below them : \[\tt\frac{8(3b-4)+10(5b+2)}{(5b+2)(3b-4)}\]
simplify the numerator
Mhmm. And do we multiply the numerators and then add them? :)
yes
\[\tt\frac{24b-4}{(5b+2)(3b-4)}+\frac{50b+2}{(3b-4)(5b+2)}\] @rational
yes, add the numerators and put the common denominator below them
\[\tt\frac{24b-4+50b+2}{(3b-4)(5b+2)}\]
@rational ^
numerator can be simplified further
combine like terms in numerator
\[\tt\frac{74b-2}{(3b-4)(5b+2)}\]
@rational ^
Hey, Mr. @rational, you still there? ._.
looks good, also you may factor out "2" from numerator
How? :)
\[\tt\frac{74b-2}{(3b-4)(5b+2)}\] \[\tt\frac{2(37b-1)}{(3b-4)(5b+2)}\]
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