CAN SOMEONE HELP? <3
Do you know how to complete the square?
sorta
(x+6)^2 = 5 is the form
solution would be x=\[\pm \sqrt{5} - 6\]
for which the top or bottom?
for top, the "form" was the (x+6)^2 = 5 part. The second one is the solution
so what is the solution? @incomplte
ughh it has two solutions, \[(+\sqrt{5}-6), (-\sqrt{5}-6)\]
ok got the answer can you help with another?
@incomplte can you show me how you got the form?
yes ma'am. Hopefully i can explain properly through this medium, but i'll try.
ok thank you (:
\[x^2 + 12x +31 = 0\] that was the question. the first thing you want to do with completing the square is to the move the constant outside
so that will be x^2 + 12x = -31
ok, i understand, keep going
then the next step, which is basically the hardest part, is to divide the "b" part of the equation by 2, then square it, and add to both sides. So let me show you.
\[x^2 + 12x +36 = -31 + 36\] so what i did was to divide 12, by 2 = 6. then square it = 36. then add to both sides
Do you get it?
how come 2?
It's just the process. Everytime you see a complete the square method, you should always divide the "b" by 2, then square the result.
ok I'm going to post another and try to do it on my own, will you tell me if im doing it correctly?
Yes i will be here.
okay so this is the question
what did you get as your form?
wait, where did 36 come from? so far im at x^2+2x=12
when you divide the "b" by 2, then you have to square it and add it to both sides of the equation. This is what they mean by "completing the square"
so 12/2^2?
for the first question, yes. (12/2)^2 = 36
ok so it should be 36?
for the first question it would be 36. But for this new one it can't be 36. because 2x is the "b" part of this equation. So if you do (2/2)^2=?
ok im not getting it then.
do you understand what i mean by the "b" part, overtime i say that?
i understand to subtract it. thats about it
damn this is really hard to explain over the internet lol
lol i know they dont believe in just giving the answer on here but you can also do that lol i ust have to answer 2 more right to move on to the next lesson
ok haha the form for it would be (x+1)^2= 13
solution would be (+sqrt(13) -1, -sqrt(13) -1)
the solution has to be in decimal form
@incomplte
do you have a calculator? i don't have one here
yes just tell me what to plug in
\[(-\sqrt{13}-1, \sqrt{13} -1)\]
there you go
@incomplte
the completed square is x=5+- radical 6
what is the form and the decimal
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