What is the formula for the following acid-base neutralization reaction? Methanoic Acid + potassium hydroxide. So far, I have 1HCOOH + 1KOH ---> ________ +1H2O
@aaronq Can you help me with this one?
HCOOH looks like this |dw:1431123452759:dw| so the end result is \(HCOO^-\) charged balanced by \(K^+\)
That wasn't right D: @aaronq
HCOOK wasn't right?
No sadly..
it has to do with the way it's being written, in terms of formatting. try KCOOH
or some variaion
Nope
I got it haha it was KHCOO
Thanks ! Can i also ask you one more question on here?
dope! yeah sure
How many grams of baking soda, NaHCO3, are needed to react with 160 mL of stomach acid having an HC1 concentration of 0.052 M? The reaction is NaHCO3(aq) + HCl(aq) NaCl(aq) + CO2(g) + H2O
so it's the same format as before. they react in a 1:1 molar ratio so: \(\sf \large M_{acid}V_{acid}=n_{base}\) find moles, n. Convert to grams
I dont remember how to convert moles to grams lol I forgot, It was one of our beginning units
with \(\sf moles=\dfrac{mass}{Molar~mass}\) you have to rearrange it though
@aaronq The answer i got was wrong, I did 160mL x 0.052M =8.32 Moles. With that, i did 8.32/84.01 to conert that to grams
molarity is in mol/L, moles per liter convert mL to L
Ohh! Okay!
and further more, to find the mass, you multiply the moles by the molar mass, not divide
Join our real-time social learning platform and learn together with your friends!