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Chemistry 17 Online
OpenStudy (anonymous):

What is the formula for the following acid-base neutralization reaction? Methanoic Acid + potassium hydroxide. So far, I have 1HCOOH + 1KOH ---> ________ +1H2O

OpenStudy (anonymous):

@aaronq Can you help me with this one?

OpenStudy (aaronq):

HCOOH looks like this |dw:1431123452759:dw| so the end result is \(HCOO^-\) charged balanced by \(K^+\)

OpenStudy (anonymous):

That wasn't right D: @aaronq

OpenStudy (aaronq):

HCOOK wasn't right?

OpenStudy (anonymous):

No sadly..

OpenStudy (aaronq):

it has to do with the way it's being written, in terms of formatting. try KCOOH

OpenStudy (aaronq):

or some variaion

OpenStudy (anonymous):

Nope

OpenStudy (anonymous):

I got it haha it was KHCOO

OpenStudy (anonymous):

Thanks ! Can i also ask you one more question on here?

OpenStudy (aaronq):

dope! yeah sure

OpenStudy (anonymous):

How many grams of baking soda, NaHCO3, are needed to react with 160 mL of stomach acid having an HC1 concentration of 0.052 M? The reaction is NaHCO3(aq) + HCl(aq) NaCl(aq) + CO2(g) + H2O

OpenStudy (aaronq):

so it's the same format as before. they react in a 1:1 molar ratio so: \(\sf \large M_{acid}V_{acid}=n_{base}\) find moles, n. Convert to grams

OpenStudy (anonymous):

I dont remember how to convert moles to grams lol I forgot, It was one of our beginning units

OpenStudy (aaronq):

with \(\sf moles=\dfrac{mass}{Molar~mass}\) you have to rearrange it though

OpenStudy (anonymous):

@aaronq The answer i got was wrong, I did 160mL x 0.052M =8.32 Moles. With that, i did 8.32/84.01 to conert that to grams

OpenStudy (aaronq):

molarity is in mol/L, moles per liter convert mL to L

OpenStudy (anonymous):

Ohh! Okay!

OpenStudy (aaronq):

and further more, to find the mass, you multiply the moles by the molar mass, not divide

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