unit quaternions, rotations, and regular octahedron... In the symmetry group of the regular octahedron what is the unit quaternion that represents 90 degree rotation about the semi x -axis lambda i , lambda > 0 The rotation appears to be counterclockwise to an observer at point A
I have a vector of just i when I am the observer at point A
so u is a unit quaternion llull = 1 where u = alpha + v -1< alpha < 1 alpha = cos theta
so if I have a 90 degree rotation already given.. wouldn't that be \[2 \theta = 90\] theta = 45 degrees and then it will be \[\frac{1}{\sqrt{2}}\]
so my equation would be \[u = \frac{1}{\sqrt{2}} = \lambda i \]
/ffffffffffff \[u = \frac{1}{\sqrt{2}}+\lambda i\]
just what is it talking about!!!! I attempted it, but not sure if it's right
What are you asking for?
here's the question : In the symmetry group of the regular octahedron what is the unit quaternion that represents 90 degree rotation about the semi x -axis lambda i , lambda > 0 The rotation appears to be counterclockwise to an observer at point A
and I'm reading this paper too.. to try and get something out of it http://www.math.unm.edu/~vageli/papers/rrr.pdf
hmmm a rotation about the x-axis by 90 degrees maps the figure to itself. wait.. go to that site and read pages 7 and 8. It has something similar to what I'm asking
I think the answer you're looking for is left multiply by "i". That's a unit quaternion that will rotate counter clockwise while looking from A.
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