Could someone help? Medal for best answer. Divide. Assume the denominator does not equal zero.
\[\frac{ 12x^2y-6xy+4x^2 }{ 2xy }\]
Please explain how to get the answer, don't just give the answer to me.
first of all compare it with this: \[\frac{ a+b+c }{ d } = \frac{ a }{ d} + \frac{ b }{ d} + \frac{ c }{ d }\] so break up your expression in th esame way into three terms
So,\[\frac{ 12x^2y }{ 2xy }+\frac{ -6xy }{ 2xy }+\frac{ 4x^2 }{ 2xy }\]
good now just cancel factors top and bottom in each term (e.g. cancel out the y in the first term)
\[6x+(-3)+\frac{ 2x }{ y }\] Like that?
That seem to be the best option in my opinion
Is there any more steps to this, or is that the answer?
well all the terms are of different 'orders' of xy so that is an acceptable answer you could collect the x terms - but this is not really a 'simpler answer: \[\frac{ x(6y+2) }{ y }-3\]
Thanks for your help :)
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