Question

Jack has a fair coin. He tosses the coin four times.

What is the probability that Jack gets heads, then heads, then tails, and then tails?

Answer 1

The question is asking for P( H & H & T & T )
Each toss is independent , therefore
P( H & H & T & T ) = P(H)* P(H) * P(T) * P (T)

Answer 2

so...what do i do? multiply?

Answer 3

@perl

Answer 4

yes you multiply and

P(Heads) = 1/2
P(Tails) = 1/2

because either side has the same chances of being landed on

Answer 5

im asking, what do i multiply? @jim_thompson5910

Answer 6

P(H)* P(H) * P(T) * P (T)

turns into

(1/2)*(1/2)*(1/2)*(1/2)

and then you evaluate that

Answer 7

1/16

Answer 8

correct

Answer 9

BTW, a unique sequence of n fair coin toss has a probability of \(2^{-n}\).