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Mathematics 13 Online
OpenStudy (anonymous):

Could someone help me with questions 3 and 4 please!! I have done 1&2 already.!!!!! P1.Using your own words, describe two events that are independent. Use math vocabulary that you have learned so far in this module to explain what it means when events are independent. Part 2: Define an issue that is important to you (politics, medicine, social media, education, etc.), and think about some things you might want to know about this issue. 1.Briefly explain your issue and what you hope to learn or understand. 2.Pose a question for which a two-way table is appropriate. Be creative here!

OpenStudy (anonymous):

3. Choose a row and column and compare P (A l B) with P (B l A) .Explain what each probability means in the context of the situation and data you collected. 4.Compare P (A (upside down 'U' B) with P (A U B), and explain what each probability means in the context of the situation and data you collected.

OpenStudy (anonymous):

My work for 2. A survey was giving to a school of 500 students. They were asked if they prefer homework or no homework. 100 boys want homework 150 girls want homework 150 boys do not want homework 100 girls do not want homework 500 student want to have and not have homework. Boys Girls Total Homework 100 150 250 No Homework 150 100 250 Total 200 200 500

OpenStudy (anonymous):

Please help... @uri

OpenStudy (anonymous):

@Nnesha

OpenStudy (anonymous):

@UnknownRandom

OpenStudy (anonymous):

@MeganLeex3

OpenStudy (anonymous):

Is this FLVS?

OpenStudy (anonymous):

yesss.......

OpenStudy (anonymous):

what subject, i might still have work from it

OpenStudy (anonymous):

algebra 2:assignment 09.04 module nine quiz

OpenStudy (anonymous):

not really a quiz

OpenStudy (anonymous):

hmm didnt take it, but try googling, sometimes you can find it, especially on open study! sorry I couldn't help :(

OpenStudy (anonymous):

i have looked every where, but no luck... Thanks for all of your help though :)

OpenStudy (anonymous):

@Nnesha any help?

OpenStudy (anonymous):

awwwww....... okay... thanks :(

OpenStudy (anonymous):

okay, thanks :)

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@jojokiw3

OpenStudy (anonymous):

@SamsungFanBoy

OpenStudy (anonymous):

@TheSmartOne

OpenStudy (amistre64):

what does it mean for 2 events to be independant?

OpenStudy (anonymous):

i guess it mean something that has two different outputs? I'm guessing

OpenStudy (anonymous):

i mean outcomes

OpenStudy (amistre64):

that doesnt sound right to me, of course i got no good way to define it either. independence means that: if the ratio of A within event B, is the same as the ratio of A within the total events, then A and B are independant. say AnB have 2 elements in common, and B has 5 elements total 2:5 is the ratio of A within B say A has 6 elements in total compared to 15 total events. 6:15 is the ratio of A within the total event space. 2/5 = 6/15, therefore A is independant of B

OpenStudy (anonymous):

okay... sooo could u help me with 3 and 4?

OpenStudy (amistre64):

maybe, id have to read them first ....

OpenStudy (anonymous):

sorry, yea i would guess so

OpenStudy (amistre64):

3. Choose a row and column and compare P (A l B) with P (B l A). Explain what each probability means in the context of the situation and data you collected. pick a row and column, and define the ratio of one within the other 4.Compare P (A (upside down 'U' B) with P (A U B), and explain what each probability means in the context of the situation and data you collected.

OpenStudy (amistre64):

upside down U is just n

OpenStudy (amistre64):

compare P(AnB) with P(AuB)

OpenStudy (amistre64):

col1 col2 Boys Girls | Total ------------ row1 Homework | 100 150 | 250 row2 No Homework | 150 100 | 250 ------------------------- Total 200 200 500

OpenStudy (amistre64):

given homework (done?), what is the probability of picking a girl?

OpenStudy (amistre64):

or rather: P(girl, given homework) , or P(g|h)

OpenStudy (anonymous):

? I really do not understand this

OpenStudy (amistre64):

given the set of homework, what is our total event space? what is total homework?

OpenStudy (amistre64):

event of homework might be more verbally correct, what is the total event space of homework?

OpenStudy (anonymous):

500?

OpenStudy (amistre64):

no, 500 is total events altogether homework is a subset of events, homework is a row, what is the total of that row?

OpenStudy (anonymous):

250

OpenStudy (amistre64):

col1 col2 Boys Girls | Total ------------ row1 Homework | 100 150 | 250 <---- total events of homework row2 No Homework | 150 100 | 250 ------------------------- Total 200 200 500 yes, 250, now probability is the simple definition of: #desired/#total our total homework event is 250, how many of those are girls?

OpenStudy (anonymous):

150

OpenStudy (amistre64):

good, so the probability of picking a girl, given that we are only concerned with homework, is 150 out of 250 P(girl | homework) = 150/250

OpenStudy (anonymous):

so 0.6

OpenStudy (amistre64):

right, so this tells us that 60% of those who do homework are girls, make sense?

OpenStudy (anonymous):

yes, so much!!!

OpenStudy (amistre64):

now, what percent of girls, do homework? given our event space is now total girls, how many of them do homework? how many girls are there in total? how many of them do home work?

OpenStudy (anonymous):

200/250?

OpenStudy (amistre64):

hmm, let do it this way, youve got an idea but its not set yet. lets take all the girls and place them in a room. we have .. i see an error in your table; 200+200 = 400; not 500 is total girls 200? or is that a typo?

OpenStudy (amistre64):

200 + 150 = 250 total if we add up the column so it might have been a typo put all girls in a room; 250 girls are i the room how many of them have done homework? 150. the probability of picking a girl that has done homework, out of all the girls; is 150/250

OpenStudy (amistre64):

100 + 150 = 250 ... even i mistype lol

OpenStudy (anonymous):

no that's the total of it all together. after i find the total of no homework and homework, i add it all together to get that big number.

OpenStudy (amistre64):

right, total events is 500 homework + no homework = 500 girls + boys = 500

OpenStudy (amistre64):

the probability of picking a girl, out of everyone thats done homework; is 150 out of 250 the probability of picking a homework, out of everyone thats a girl; is 150 out of 250 its not a very exciting table ....

OpenStudy (amistre64):

dinners ready .....

OpenStudy (anonymous):

sorry, i had to do something for my mom!!!!! u still there?

OpenStudy (anonymous):

would u like to change the table?

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

can we change the table?

OpenStudy (amistre64):

boys girls homework 58 62 120 no homework 23 22 45 81 84 165 now we have some numbers that wont "be the same"

OpenStudy (amistre64):

given the subevent of homework: set everyone in a room that has homework (120 of them) whats the probability of picking a girl? 62/120 the probability of picking someone that is a girl, given that a person has done homework is 62/120 ---------------------------------------- given the subevent of girls: set everyone in a room that is a girl (84 of them) whats the probability of picking one that has homework? 62/84 the probability of picking someone that has homework, given that they are a girl is 62/84 ---------------------------------------- notice that the probability changes depending on the specific event that we are trying to determine.

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

ah, this one its too long and is causing me lag .... can we post it new?

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