Question

100 mL of 0.25 M acetic acid (HAc) solution (aqueous) is prepared (Ka = 1.9x10^-5). Calculate the pH.

Answer 1

To solve for the pH of .25M acetic acid you need to set up an ICE box equation.


Then, solve for x by setting the Ka equal to x^2 over .25

x will equal the [H+] in this case, it equals .0021794 M

then take the negative log of .0021794 to get the pH of the solution. =~2.6