Determine the radius of the circle. Use the point (-11, 6) on the circle to find the radius.
and the center is -5, 2
@jdoe0001
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OpenStudy (jdoe0001):
hehehe
OpenStudy (18jonea):
what? @jdoe0001
OpenStudy (jdoe0001):
|dw:1431212766684:dw|
notice, the radius is the "distance" between the center and the point "on" the circle
thus use the distance formula then
\(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({\color{red}{ -11}}\quad ,&{\color{blue}{ 6}})\quad
% (c,d)
&({\color{red}{ -5}}\quad ,&{\color{blue}{ 2}})
\end{array}\qquad
% distance value
d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)
OpenStudy (18jonea):
what is d
OpenStudy (jdoe0001):
yeah... what is it, use the distance formula, "d" is just the "distance" or radius in this case
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OpenStudy (18jonea):
-5 +11= 6 2-6 = -4
OpenStudy (18jonea):
@jdoe0001
OpenStudy (jdoe0001):
yeap
OpenStudy (18jonea):
so 36+16 = 52
OpenStudy (18jonea):
@jdoe0001
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OpenStudy (jdoe0001):
yeap
OpenStudy (18jonea):
approximately 7.21
OpenStudy (18jonea):
@jdoe0001
OpenStudy (jdoe0001):
well...if you wan to round it up, yes
OpenStudy (18jonea):
ok thanks
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OpenStudy (jdoe0001):
yw
OpenStudy (18jonea):
lastly how would you write the standard equation for this
OpenStudy (18jonea):
@jdoe0001
OpenStudy (18jonea):
@Nnesha
OpenStudy (18jonea):
@jdoe0001
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Nnesha (nnesha):
\(\bf (x-{\color{brown}{ h}})^2+(y-{\color{blue}{ k}})^2={\color{purple}{ r}}^2
\qquad center\ ({\color{brown}{ h}},{\color{blue}{ k}})\qquad
radius={\color{purple}{ r}}\)
plug in the given values
~jdoe0001