Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (babynini):

Help me solve this!

OpenStudy (babynini):

OpenStudy (babynini):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

when k = 1, what is the value of 7/18 + k/3 ?

OpenStudy (babynini):

13pi/18?

jimthompson5910 (jim_thompson5910):

yes, I took out the pi's temporarily but you have the right idea

jimthompson5910 (jim_thompson5910):

you'll do the same for other positive whole numbers for k until you get to 2pi (you stop if you go over 2pi)

OpenStudy (babynini):

How do I know when i've reached 2pi? (that's probably a silly question but I don't know xD)

jimthompson5910 (jim_thompson5910):

2pi = 6.28 approximately evaluate each of the fractions you get and see if they are smaller than 6.28

OpenStudy (babynini):

so 37pi/18 would be too large already?

jimthompson5910 (jim_thompson5910):

37pi/18 = 6.45771823237901 so yes it's too big

OpenStudy (babynini):

It didn't like this answer D:

jimthompson5910 (jim_thompson5910):

it says at the top "round your answers to 3 decimal places where appropriate" so maybe they want them in decimal form?

OpenStudy (babynini):

hm ok. Should the 7pi/18 be in that box too, or no?

jimthompson5910 (jim_thompson5910):

the decimal form of it, yes

jimthompson5910 (jim_thompson5910):

hmm wait, if k = -1, then 7/18 + k/3 = 1/18 so pi/18 is part of the solution set as well pi/18 = 0.17453 is in the interval [0,2pi)

OpenStudy (babynini):

ah, ok, i'll try that. Because it didn't like that last answer either even in decimal.

OpenStudy (babynini):

It still doesn't like it D: idk how many more tries I have. If any.

jimthompson5910 (jim_thompson5910):

so you tried the exact form? with pi/18 included?

OpenStudy (babynini):

ai, I don't have any more tries actually -.- No, I didn't :/

OpenStudy (babynini):

well i tried the decimal form with pi/18 included

jimthompson5910 (jim_thompson5910):

I see. You either would do everything in decimal form or in exact fraction form (keeping pi intact)

OpenStudy (babynini):

Yeah, i'm thinking maybe they wanted it in exact fraction form. Ah, well.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!