Question

The spin cycle on a washing machine slows from 900 to 300 rev/min in 4 sec.
- Determine the angular acceleration during the slowing down.
When the cycle operates at 900 rev/min the output power is 4 kW.
- What is the Torque developed?
- If the radius of the tub is 30 cm, what is the linear speed near the inside border ?

Answer 1

Clue
Angular acceleration is the rate of change of angular velocity
\[\alpha = \frac{\Delta \omega}{\Delta t}\]

But angular velocity has to be in S.I. units, so you have to convert revs/min to rads/ sec

Power and torque are connected as
\[P = \tau \omega\]

Finally angular speed and linear speed are connected as
\[v = r \omega\]

Answer 2

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Answer 3

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