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Mathematics 8 Online
OpenStudy (anonymous):

How do I convert f(x) = x^2+6x-16 into general standard form?

TheSmartOne (thesmartone):

Hi there, Welcome to OpenStudy! What is the general standard form for an equation?

OpenStudy (anonymous):

ax+bx=c I think

TheSmartOne (thesmartone):

For a quadratic equation, it would be: \(\sf f(x) = a(x - h)^2 + k\), where a \(\neq\) 0

TheSmartOne (thesmartone):

The vertex of the function is (h, k).

OpenStudy (anonymous):

Oh okay. So I have to find the vertex first using -b/2a

TheSmartOne (thesmartone):

And that is for the equation: \(\sf f(x) = ax^2 + bx + c\)

TheSmartOne (thesmartone):

Yes, we can find the vertex like that :)

OpenStudy (anonymous):

Okay thank you so much!

TheSmartOne (thesmartone):

And to make sure, you can graph what you were given originally and what you came up with at the end. And make sure that they are the same graph. :)

TheSmartOne (thesmartone):

You can use http://www.desmos.com/calculator

OpenStudy (anonymous):

Okay thank you

OpenStudy (anonymous):

The answer I get for the vertix is that h?

TheSmartOne (thesmartone):

correct, and then you plug that back in to what we were originally given and calculate for k.

OpenStudy (anonymous):

Okay thanks again :)

TheSmartOne (thesmartone):

anytime :)

TheSmartOne (thesmartone):

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