Question

What is the equation of the circle with the center (-6, 7) that passes through the point (4, -2)? @flight98

Answer 1

\[\huge\rm (x-h)^2 + (y-k)^2 = r^2\]
where (h,k) is the center
and passing trough the point (x,y)
so replace variables by their values and then solve for r(radius)

Answer 2

(h,k) ( -6,7) center
(x,y)(4,-2)

Answer 3

I'm not sure how to do this....

Answer 4

use that equation i gave u
first of all replace h and k by (-6,7)
and x ,y by (4,-2)

Answer 5

\[\huge\rm (\color{blue}{x}-\color{red}{h})^2 + (\color{blue}{y}-\color{red}{k})^2 = r^2\]
\[\huge\rm (\color{red}{-6,7})\]
\[\huge\rm (\color{blue}{4,-2})\]

Answer 6

These are my options...

Answer 7

okay so plug in (h,k) and (x,y) values into the equation

Answer 8

\[\huge\rm (\color{blue}{4}-\color{red}{h})^2 + (\color{blue}{-2}-\color{red}{k})^2 = r^2\]
\[\huge\rm (\color{red}{-6,7})\]
\[\huge\rm (\color{blue}{4,-2})\]
that's how you should replace x and y by their value
now plug in (h,k) values into the equation

Answer 9

I don't know

Answer 10

i'm not saying tell me the answer
just replace h by -6 and k by 7 and then show ur work that's it
then we will solve it together