Question

For the gas-phase reaction:

2 AZ ↔ A2 + Z2

Kc = 16 at 523 K. If 0.030 mol of AZ is initially introduced into a 1.00 L vessel at 523 K, then at equilibrium, [Z2] = ______M.

Answer 1

i think this is how you do it :P

Answer 2

wouldn't you have to do (.3-x)^2? if you're doing an ICE table

Answer 3

I'm also really confused that it gives the temp and specifies that its a gas phase reaction. i feel like i'm suppose to convert to kp but i dont know if thats right or not

Answer 4

YES, but you assume that the value of x is negligible and you leave it as .3^2

Answer 5

1.2 isn't one of the options i'm given :(

Answer 6

well what are the options given?

Answer 7

A)
0.0052


B)
0.013


C)
0.24


D)
0.0030


E)
0.017

Answer 8

oh the questions says .03 moles and i had been using .3 moles smh

Answer 9

also to answer your question earlier you dont have to convert to Kp for this question

Answer 10

the answer is .013

Answer 11

i honestly dont know how to get to it but i found this problem set for FIU trying to understand how to do the problem http://www2.fiu.edu/~gravesp/1046%20Practice%20Sheets/e2_sp_02_practice.pdf

Answer 12

it has this problem and several related problems

Answer 13

I asked a classmate. she said you have to do\[16=\frac{ x ^{2} }{ (.03-2x)^2 }\]

Answer 14

then square root both sides to get \[4=\frac{ x }{ 0.03-2x }\]

Answer 15

Oh i see how that makes sense if you derived it directly from an ICE table as the change in x for AZ would be -2x but only +x for A2 and Z2

Answer 16

cant believe i missed that :/

Answer 17

Lol thats okay. I'm just studying for my final tomorrow so the specific question isn't what matters. its just knowing how to do it

Answer 18

alright gl i just recently took the chem ap :P happy studying

Answer 19

Thanks Lol i'm in chem 104 in college. Have to take organic chem next semester so I really have to get a grasp on the basics to be able to move on