Question

how many real roots does the function f(x)=x^2-3x+4 have?


A.
–7
B.
0
C.
1
D.
2

Answer 1

lol surely not-7

Answer 2

2?

Answer 3

solve \[x^2-3x+4=0\] and see

Answer 4

or since you are not actually asked for the solutions, compute
\[b^2-4ac\] with \(a=1,b=-3,c=4\)

Answer 5

once you see that the answer is negative, that means there are no solutions

Answer 6

yeah i equaled it out to be one half something

Answer 7

obviously 2 real roots

Answer 8

so that means its 0??

Answer 9

i believe its 0

Answer 10

yeah
\[(-3)^2-4\times 1\times 4=9-16=\text{some negative number}\]

Answer 11

so no real solutions for sure

Answer 12

thank you @satellite73

Answer 13

yw