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Solve the following system. 4x^2 + 9y^2 =72 x^2 - y^2 = 5 The solutions are: (), (), (), and () (remember to include the commas)
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@paki
solving for y from eq1 when x = 3 4x^2 + 9y^2 = 72 4(3)^2 + 9y^2 = 72 36 + 9y^2 = 72 9y^2 = 72 - 36 9y^2 = 36 y^2 = 4 y = ± √(4) y = ± 2 y = 2, -2
@Lolipop_Drum312 That does not look like a solution to me. You have chosen x=3 and x=-3 but not 'solved' for them
Here is how you do it. Multiply the second equation by 9 to get 4x^2 + 9y^2 = 72 9x^2 - 9y^2 = 45 Add them to get 13x^2 = 117 ----> x^2 = 9 ----> x = +/- 3. Now substitute in the second original equation to get y
That is correct
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