Mathematics
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OpenStudy (anonymous):
What is the distance between points (9, 4) and (–3, 4) on a coordinate plane?
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OpenStudy (igreen):
Use the distance formula.
OpenStudy (anonymous):
what is that
OpenStudy (igreen):
\(\sf d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)
OpenStudy (igreen):
(9, 4), (-3, 4)
x1 y1 x2 y2
OpenStudy (anonymous):
so I have to complete the fomula
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OpenStudy (anonymous):
I am confused
OpenStudy (anonymous):
yes. replace the x1 ,x2 and y1, y2 with the numbers.
OpenStudy (igreen):
Yes
OpenStudy (igreen):
\(\sf d = \sqrt{(-3-9)^2 + (4-4)^2}\)
OpenStudy (anonymous):
yes. now solve it
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OpenStudy (igreen):
Oh, well since they have the same y-value, we can just subtract the two numbers.
|9 - (-3)|
OpenStudy (anonymous):
how do I solve it
OpenStudy (igreen):
Just subtract
|9 - (-3)|
OpenStudy (anonymous):
have you learned subtraction addition and multiplication?
OpenStudy (anonymous):
yes but that thing with all the numbers how do I do that
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OpenStudy (anonymous):
igreen has got it down where now all u have to do is subtract 9 from -3
OpenStudy (anonymous):
d= what is that
OpenStudy (anonymous):
dont worry about that part. we are solving for D, as of right now D doesnt matter
OpenStudy (anonymous):
12
OpenStudy (anonymous):
d represents the distance.
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OpenStudy (anonymous):
12=9 - -3
OpenStudy (anonymous):
no D= 9-(-3) then when u solve that D=12
OpenStudy (anonymous):
see what i am talking about?
OpenStudy (anonymous):
ya
OpenStudy (anonymous):
so your distance is 12
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OpenStudy (anonymous):
ya
OpenStudy (anonymous):
problema resuelto
OpenStudy (anonymous):
what
OpenStudy (anonymous):
problem solved
OpenStudy (anonymous):
okay