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Mathematics 8 Online
OpenStudy (anonymous):

help me in physics

OpenStudy (anonymous):

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OpenStudy (anonymous):

@IrishBoy123

OpenStudy (anonymous):

@uri

OpenStudy (anonymous):

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OpenStudy (anonymous):

I can't really help you since some of the question is cut off, so I really don't know what they are asking you, sorry!

OpenStudy (anonymous):

when a certain 1.5 V battery is used to power a 3.0 W flashlight bulb it is exhausted after an hours use. a. how much chargedhas passed through the bulb in this period of time? b. if the electric energy obtained in this way? c. how does this comparewith the cost of the electric energy supplied to your home which is about php 11.50/kwh

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

we have to compute the intensity of current which flows into your flashlight bulb, first

OpenStudy (anonymous):

yes,

OpenStudy (michele_laino):

the intensity of current, is given by the subsequent relationship: \[\Large I = \frac{W}{V}\] where W is the power, and V is the voltage applied to our flashlight bulb

OpenStudy (anonymous):

so 3.0/1.5 = 1.5

OpenStudy (michele_laino):

that's right! The current is 1.5 amperes

OpenStudy (anonymous):

so whats next

OpenStudy (michele_laino):

Now, the requested charge Q, is given by the subsequent formula: \[\Large Q = I \times \Delta t\] where \Delta T is time, measured in seconds, and Q is measured in Coulombs

OpenStudy (anonymous):

theres no given time

OpenStudy (anonymous):

1 hour only

OpenStudy (michele_laino):

time is 1 hours=3600 seconds

OpenStudy (michele_laino):

hour*

OpenStudy (anonymous):

yes so, 1.5 A (3600s( = 5400

OpenStudy (michele_laino):

that's right! Total charge is Q=5400 coulombs

OpenStudy (anonymous):

ys

OpenStudy (anonymous):

next is the battery cost

OpenStudy (michele_laino):

now, the energy E absorbed by our flashlight bulb is given by the subsequent formula: \[\Large E = W \times \Delta t = 0.003 \times 1 = ...?{\text{kWh}}\] please note that I have measured the power in KWatt, and time in hour, in order to get the energy in kWh

OpenStudy (anonymous):

= 3x10-3

OpenStudy (michele_laino):

since 3 Watt= 3/1000=0.003 kWatt

OpenStudy (michele_laino):

that's right!

OpenStudy (michele_laino):

now, in order to get the total cost, you have to multiply that energy by the specific cost, namely 11.50, so we have: \[\Large {\text{total cost }} = {\text{ }}11.50 \times 3 \times {10^{ - 3}} = ...?\]

OpenStudy (anonymous):

= 0.0345 php

OpenStudy (michele_laino):

that's right!

OpenStudy (anonymous):

what abot the if the battery cost 9 php

OpenStudy (michele_laino):

that means our flashlight bulb can be powered, with that battery for at least 9/0.0345=...? hours

OpenStudy (anonymous):

my problem is incomplete when a certain 1.5 V battery is used to power a 3.0 W flashlight bulb it is exhausted after an hours use. a. how much chargedhas passed through the bulb in this period of time? b. if the battery cost Php 9.00 , what is the cost of a kilowatt hour of electric energy obtained in this way? c. how does this comparewith the cost of the electric energy supplied to your home which is about php 11.50/kwh

OpenStudy (anonymous):

thats the problem

OpenStudy (michele_laino):

in that case, in order to find the specific cost, we have to compute this: \[\Large \frac{9}{{0.003}}\]

OpenStudy (anonymous):

whats the formula used

OpenStudy (anonymous):

=3000

OpenStudy (michele_laino):

cost of battery/ absorbed energy

OpenStudy (michele_laino):

that's right!

OpenStudy (anonymous):

whats the unit

OpenStudy (michele_laino):

php/kWh

OpenStudy (anonymous):

ojkay then how about letter b

OpenStudy (anonymous):

i mean c

OpenStudy (michele_laino):

here it is suffice to compute this ratio: \[\frac{{3000}}{{11.50}} = ...?\]

OpenStudy (anonymous):

= 280.87, whats the formula

OpenStudy (michele_laino):

I got 260.87. I used this formula: \[\Large \frac{{{\text{specific cost using battery}}}}{{{\text{specific cost using electricity of home}}}}\]

OpenStudy (michele_laino):

that ratio indicates taht the electricity supplied by battery is more expensive than the electricity supplied by the home electricity

OpenStudy (anonymous):

ah yes its 260.87 what should be the explanation

OpenStudy (michele_laino):

yes!

OpenStudy (anonymous):

tthankyou very very much

OpenStudy (michele_laino):

thank you! :)

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