help me in physics
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@IrishBoy123
@uri
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I can't really help you since some of the question is cut off, so I really don't know what they are asking you, sorry!
when a certain 1.5 V battery is used to power a 3.0 W flashlight bulb it is exhausted after an hours use. a. how much chargedhas passed through the bulb in this period of time? b. if the electric energy obtained in this way? c. how does this comparewith the cost of the electric energy supplied to your home which is about php 11.50/kwh
@Michele_Laino
we have to compute the intensity of current which flows into your flashlight bulb, first
yes,
the intensity of current, is given by the subsequent relationship: \[\Large I = \frac{W}{V}\] where W is the power, and V is the voltage applied to our flashlight bulb
so 3.0/1.5 = 1.5
that's right! The current is 1.5 amperes
so whats next
Now, the requested charge Q, is given by the subsequent formula: \[\Large Q = I \times \Delta t\] where \Delta T is time, measured in seconds, and Q is measured in Coulombs
theres no given time
1 hour only
time is 1 hours=3600 seconds
hour*
yes so, 1.5 A (3600s( = 5400
that's right! Total charge is Q=5400 coulombs
ys
next is the battery cost
now, the energy E absorbed by our flashlight bulb is given by the subsequent formula: \[\Large E = W \times \Delta t = 0.003 \times 1 = ...?{\text{kWh}}\] please note that I have measured the power in KWatt, and time in hour, in order to get the energy in kWh
= 3x10-3
since 3 Watt= 3/1000=0.003 kWatt
that's right!
now, in order to get the total cost, you have to multiply that energy by the specific cost, namely 11.50, so we have: \[\Large {\text{total cost }} = {\text{ }}11.50 \times 3 \times {10^{ - 3}} = ...?\]
= 0.0345 php
that's right!
what abot the if the battery cost 9 php
that means our flashlight bulb can be powered, with that battery for at least 9/0.0345=...? hours
my problem is incomplete when a certain 1.5 V battery is used to power a 3.0 W flashlight bulb it is exhausted after an hours use. a. how much chargedhas passed through the bulb in this period of time? b. if the battery cost Php 9.00 , what is the cost of a kilowatt hour of electric energy obtained in this way? c. how does this comparewith the cost of the electric energy supplied to your home which is about php 11.50/kwh
thats the problem
in that case, in order to find the specific cost, we have to compute this: \[\Large \frac{9}{{0.003}}\]
whats the formula used
=3000
cost of battery/ absorbed energy
that's right!
whats the unit
php/kWh
ojkay then how about letter b
i mean c
here it is suffice to compute this ratio: \[\frac{{3000}}{{11.50}} = ...?\]
= 280.87, whats the formula
I got 260.87. I used this formula: \[\Large \frac{{{\text{specific cost using battery}}}}{{{\text{specific cost using electricity of home}}}}\]
that ratio indicates taht the electricity supplied by battery is more expensive than the electricity supplied by the home electricity
ah yes its 260.87 what should be the explanation
yes!
tthankyou very very much
thank you! :)
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