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Mathematics 11 Online
OpenStudy (anonymous):

Can someone please help me Find functions f and g so that h(x) = (f ∘ g)(x).

OpenStudy (anonymous):

h(x) = (6x - 14)8

OpenStudy (anonymous):

@nincompoop @ParthKohli @iGreen

OpenStudy (anonymous):

hi pearl nice to see you again

OpenStudy (perl):

Hi :) Did I copy this correctly $$ \Large h(x) = (6x-14)\cdot 8 $$

OpenStudy (anonymous):

no it ^8

OpenStudy (perl):

$$\Large h(x) = (6x-14)^8$$

OpenStudy (anonymous):

yes :)

OpenStudy (perl):

the 'inner' function is y = 6x-14 the 'outer' function y = u^8

OpenStudy (anonymous):

how do you know this out of curiosity

OpenStudy (anonymous):

and is the answer im trying to find just the inner and outer functions or does it go more in depth

OpenStudy (perl):

basically by inspection (looking at it)

OpenStudy (anonymous):

ok

OpenStudy (perl):

$$\Large h(x) = f(g(x))$$ Let the inner function be g(x) = 6x-14 g takes x in, spits out 6x-14 then f takes 6x-14 and raises it to a power of 8 f(x) = x^8

OpenStudy (perl):

|dw:1431355369880:dw|

OpenStudy (anonymous):

that seems way to simple for pre calculus i mean theres no calculations to do or nothin?

OpenStudy (perl):

the g function or machine takes x, multiplies by 6 and adds 14 the f function or machine takes whatever comes inside and raises it to power of 8

OpenStudy (anonymous):

shouldnt it be subtracts 14 not adds

OpenStudy (perl):

woops

OpenStudy (anonymous):

what

OpenStudy (perl):

|dw:1431355593761:dw|

OpenStudy (perl):

typo , should be minus 14

OpenStudy (perl):

|dw:1431355672166:dw|

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