Question

a metal rod 1.o m long and 10milimmeeter in diameter is drawn out into wire 1.0mm indiameter. a. what is the length of the wire? b. compare the resistance of the rod with that of the wire

Answer 1

@Michele_Laino

Answer 2

here the volume of the wire has to to be equal to the volume of the metal rod

Answer 3

yess

Answer 4

so, being the volume V of a cylinder given by the subsequent formula:
\[V = \frac{{\pi {D^2}}}{4} \times L\]
where L is the length and D is the diameter of the cylinder,
we can write:
\[\Large \frac{{\pi \times {{10}^2}}}{4} \times {10^3} = \frac{{\pi \times {1^2}}}{4} \times L\]
where L is the requested length. Please note that I have measured the diameters and the known length of the cylinder in millimeters

Answer 5

yes then whats nest

Answer 6

V is not given too

Answer 7

we have to compute the length L from that formula above