Question

Hii so this is a calc question! Can someone help me find the value of the following limits? (Both of them require the use of L' Hopital's rule!)

Answer 1

^That's what I have so far for b!

Answer 2

thats an algebraic nightmare,

Answer 3

so its wrong? @amistre64

Answer 4

i cant think of a convenient way to simplify it .... its not wrong, its just a pain

Answer 5

if we take out the error element of doing things by hand, and let the wolf take the derivatives, we get down to this

(xe^2x + xe^x -2e^2x +2e^x)/(e^x-1)^3


(2xe^x + x - 3e^x+3)/(3 (e^x-1)^2)


(2x +e^(-x) -1)/(6(e^x-1))


(2-e^(-x))/(6e^x)

Answer 6

i believe you have an error creep in when you derived to the 5th line

(2xe^x + x - 3e^x+3)/(3 (e^x-1)^2) , we are good to here


2e^x +2xe^x + 1 - 3e^x +0
-----------------------
6e^x (e^x-1)



2xe^x + 1 - e^x
---------------
6e^x (e^x-1)



2x + e^(-x) - 1
---------------
6 (e^x-1)


which then we can take the last derivative