Five of the six exterior angle measures of a nonregular hexagon measure 55°, 60°, 69°, 57°, and 57°. What is the measure of the interior angle adjacent to the sixth exterior angle? a. 128° b. 118° c. 62° d. 108°
You need to know the sum of the measures of the exterior angles of a polygon, one angle per vertex. That sum is 360 deg.
okay then ?
The sum of the measures of all the exterior angles is 360. You have 5 measures, so add them up and subtract the sum from 360. That gives you the sixth exterior angle.
That is not your final answer yet because the problem wants the measure of the sixth interior angle.
62 im i right
Yes. That is the measure of the 6th exterior angle. Now you need the measure of the 6th interior angle.
Find the sum of the measures of the interior angles of the figure. a. 1,080° b. 900° c. 1,620° d. 1,260°
can you help me with this one
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Wait. First, we're not done with the first problem. Second, if you need help with another problem, then start a new post for it. The rule is one problem per post. I'll help you with your new problem in a new post, but let's finish the first problem first.
Look at my figure above. What is the relationship between an interior and an exterior angle at the same vertex of a polygon?
i dont really know
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