Question

Can someone help me here:

Answer 1

please be polite with moderators, otherwise I don't help you! @Howard-Wolowitz

Answer 2

The problem seems to leave the amount of time up to the person making draft and further seems to indicate that the period of time is the same for each graph.

Answer 3

*draft - graph

Answer 4

Let's suppose be N the number of vehicle in 2° and central ave
and let's suppose that T is time within we have counted that number N of vehicles
Then number of vehicle per unit timein 2° and central Ave is:
N/T

Answer 5

namely N/T is the traffic flows in 2° and Central Ave

Answer 6

From the text of your problem we can write that the traffic flow in 1st Ave and High St, is twice with respect to the traffic flow in 2nd and central Ave, so we can write:
traffic flows in 1st and High street is:
2(N/T)
Now we have:
\[\Large 2\frac{N}{T} = \frac{N}{{\left( {T/2} \right)}}\]

Answer 7

alright I gotcha so far

Answer 8

but what if the streets over-lapped

Answer 9

I don't know, in this case our streets are different streets

Answer 10

so, what is the right option?

Answer 11

Well B

Answer 12

are you sure?
reassuming:
the traffic flow in 2nd and central Ave, is:
\[\Large\frac{N}{T}\]
whereas, the traffic flow at 1st and High street is:
\[\Large \frac{N}{{\left( {T/2} \right)}}\]
please look at the denominators of both fractions

Answer 13

So it would be half as long?

Answer 14

yes! So what is the right option, please?

Answer 15

A

Answer 16

that's right!

Answer 17

awesome thanks for the help

Answer 18

thanks! :)