(cos Θ − cos Θ)2 + (cos Θ + cos Θ)2 sin2 Θ 4cos2 Θ 8 cos2 Θ
@JoannaBlackwelder Do you know how to solve?
@MathStudent420
the first one cancels costheta -costheta=0 \[(\cos \theta +\cos \theta)^2=(2\cos \theta)^2=4\cos^2 \theta\]
That is what I had! Ugh feels great to be right. Canyou help with one more?
f(x) = 2 sin(2x − π) + 2 g(x) graph of a quadratic with points at 1, 2 and 3, negative 2 and 5, 2 h(x) x y −2 10 −1 7 0 5 1 3 2 5 3 7 4 10 Which function has the smallest minimum? All three functions have the same minimum f(x) g(x) h(x)
hmm the first has minimum whenever 2sin(2x-pi)+2=-1 the second do you mean points (1,2) (3,-2) (5,2)? the third has minimum at x=1 which is 3
It's a parabola on a graph.
first you would have to solve to find where exactly the min occurs
The bottom of the parabola which is at -2
-2 would be the minimum the way you wrote it is not good that's why i'm asking you should write ordered pairs (x,y) like this
It is a chart, hold on let me send u a picture of it
solve the first one to get the min
\[2\sin (2x-\pi)+2=-1 \]
That is the graph they give
yeah the min for that is -2
and for h(x) it is -2 as well
no it is 3 according to that table
oh ok the smallest is g(x)???? Because we have -1,-2, and 3
hmm no the first is not -1 you have to solve to see where that occurs
do you know how to solve such equations?
no I dont think so
is this calculus based question + how come you don't know how to solve equations that involve trigonometry? it is part of algebra 1 or so
Algebra 2
I forgot how to solve it!
will look for how to do it then
well*1
i believe you are given in notes how to deal with sins and cosine and how to get min and max
We are. Is the answer on the graph -3.3?
given \[f(x)=A\sin(Bx-C)+D\] the min is D-|A| in our example \[f(x)=2\sin(2x-\pi)+2\] the min is 2-2=0
So g(x) is still the answer?
yeah
Thanks so much for your help
np
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