Question

last one! help?

Answer 1

@Here_to_Help15
@Abhisar
@Michele_Laino
@dan815
@amistre64
@TheSmartOne
@JFraser
@e.mccormick

Answer 2

yay i was the first lol

Answer 3

;)

Answer 4

Crap im late for my appointment hmu later cya

Answer 5

please wait a moment since I have to help another student

Answer 6

ok

Answer 7

we can rewrite your polynomial as follows:
I factor out x^2 between the first and second term:
\[\Large {x^3} - {x^2} - x + 1 = {x^2}\left( {x - 1} \right) - \left( {x - 1} \right)\]
where I have factored out -1, between the third and fourth term

Answer 8

@jessmitz

Answer 9

next I factor out x-1, so I get:
\[\Large \begin{gathered}
{x^3} - {x^2} - x + 1 = {x^2}\left( {x - 1} \right) - \left( {x - 1} \right) = \hfill \\
\hfill \\
= \left( {x - 1} \right)\left( {{x^2} - 1} \right) = \hfill \\
\hfill \\
= \left( {x - 1} \right)\left( {x - 1} \right)\left( {x + 1} \right) = \hfill \\
\hfill \\
= {\left( {x - 1} \right)^2}\left( {x + 1} \right) \hfill \\
\end{gathered} \]

Answer 10

so it's false?

Answer 11

that's right! Since the exponent of the factor (x-1) is 2 and not 3

Answer 12

that makes sense! thank you so much!!

Answer 13

thank you! :)