PLEAAAAAAAAAAASEEEE I NEED YOUR HELP!! Evaluate sin 60° without using a calculator by using ratios in a reference triangle. @igreen
@surjithayer PLEEEEEEEEEEASEE HELP!!
Okay, first thing we see is a 60 degree angle...what right triangle has a 60 degree angle? a 30 60 90 triangle right? which *you can look it up* has side ratios: |dw:1431382086528:dw|
right
For future reference there are only 2 reference triangles a 30 60 90 triangle and a 45 45 90 triangle with those, you can solve any trig ratio
But here, we need the sin of 60 degrees, so we are working with this triangle so we find the angle of 60 |dw:1431382255318:dw|
okay
And now, what do we know about the "sin" of a right triangle? which sides are involved?
Just in case we don't know there is an easy way to remember SOH-CAH-TOA S in O pposite H yotenuse C os A djacent H ypotenuse T angent O pposite A djacent So we can see here that "sin" is equal to the opposite over the hypotenuse \[\large sin\theta = \frac{opposite}{hypotenuse}\] right?
right i see that
Correct
@johnweldon1993
Not a problem :)
@johnweldon1993 done
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