A hard candy has a radius of 9 mm. The candy has a spherical soft center with a radius of 6 mm, with a hard shell surrounding it.
What is the volume of the hard shell?
Use 3.14 to approximate pi and express your final answer in hundredths.
??? mm^3
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OpenStudy (anonymous):
So just do total volume of hard candy - volume of soft center
OpenStudy (twizttiez):
Sorry but like I'm not good at math :'( could you help me with the formula??
OpenStudy (anonymous):
Volume of a sphere is \[\frac{ 4 }{ 3 }\pi*r^3\] Just put in the radius value and calculate in a calculator.
OpenStudy (twizttiez):
Okay one second!
OpenStudy (twizttiez):
288??
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OpenStudy (twizttiez):
288pi
OpenStudy (anonymous):
How in the world did you get that answer?
OpenStudy (twizttiez):
I used 6 as my radius :/
OpenStudy (twizttiez):
With 9 I got 972pi
OpenStudy (anonymous):
You should have done\[(\frac{ 4 }{ 3 }\pi*9^3)-(\frac{ 4 }{ 3 }\pi*6^3)\] And you are supposed to use 3.14 as pi, so pi shouldn't be in the answer itself.
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OpenStudy (anonymous):
Ok, I see what you did wrong. Subtract 288pi from 972 pi and then multiply the answer by 3.14
OpenStudy (twizttiez):
Ohhhhhh okay thanks so much
OpenStudy (anonymous):
What did you get for your answer?
OpenStudy (twizttiez):
Wait do I subtract 972 by 288 or the other way around?
OpenStudy (twizttiez):
???
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OpenStudy (anonymous):
972-288
OpenStudy (twizttiez):
Okay thanks
OpenStudy (anonymous):
You're welcome
OpenStudy (twizttiez):
I got 2148.84937506
OpenStudy (twizttiez):
Right @LegendarySadist
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OpenStudy (twizttiez):
6747.38703769 this is what I got after I multiplied it by pi