Question

Find the exact value.

Sec^2(11pi/6)

Answer 1

hmmm kinda missing the \(\pi\) there.. shoot

Answer 2

\(\bf sec(\theta)
=\cfrac{1}{cos(\theta)}
\\ \quad \\

sec^2\left( \frac{11\pi }{6}\right)\implies \left[ sec\left( \frac{11\pi }{6}\right) \right]^2\implies \left[ \cfrac{1}{cos\left( \frac{11\pi }{6}\right)} \right]^2
\\ \quad \\
\cfrac{1^2}{cos^2\left( \frac{11\pi }{6}\right)}\implies \cfrac{1}{cos^2\left( \frac{11\pi }{6}\right)}\implies \cfrac{1}{\left[cos\left( \frac{11\pi }{6}\right)\right]^2}\)

Answer 3

so just get \(\bf cos\left( \frac{11\pi }{6}\right)\) from the Unit Circle, and square it

Answer 4

Thank you so much!

Answer 5

yw