Question

Find dy/dx by implicit differentiation.
y=tan(x+y)

Answer 1

I got this so far:
\[y'=\frac{ \sec^2(x+y) }{ -\tan^2(x+y) }\]

Answer 2

That looks almost right, but when you do the chain rule, it should look like this:

\(y'=\sec^2(x+y) * (x+y)' \)

But you can evaluate this further.

Answer 3

oh okay. I got it now.