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Mathematics 11 Online
OpenStudy (anonymous):

What is the variance of the data set? 63 54 62 59 52 (Points : 1) 11.6 14.5 18.8 23.5

OpenStudy (anonymous):

@rishavraj

OpenStudy (amistre64):

id subtract 52 from them all and then work it .. if i had to do it by hand

rishavraj (rishavraj):

hmmmmm u know how to calculate the variance.... u need to find the average of the numbers first

OpenStudy (anonymous):

i dont know how to calculate the variance

OpenStudy (amistre64):

63 54 62 59 52 11 2 10 7 0 subtract another 6 5 -4 4 1 -6 this set is simpler to work by hand, and has the same variance

OpenStudy (amistre64):

i guess 57 was the mean of the larger set, cause its 0 now

OpenStudy (anonymous):

Why 6? I still am entirely confused

rishavraj (rishavraj):

\[mean = \frac{ 63 + 54 + 62 + 59 + 52 }{ 5 }\]

OpenStudy (amistre64):

all i did was shift the data set to smaller values, the varaince doesnt change since we still have the same internal measures

OpenStudy (amistre64):

mean was 58 now, variance is determined by subtracting the mean from the data points anyways, to zero things out.

OpenStudy (amistre64):

i just happened to get it zeroed out on a whim :) take the average of the squared results

OpenStudy (anonymous):

5 -4 4 1 -6 square these out?

OpenStudy (amistre64):

yep

OpenStudy (amistre64):

we would have subtracted the mean of that smaller set from its values, but the mean just happened to be 0 ... soo, square, sum, divide by 5

rishavraj (rishavraj):

@LeilaJudeh http://www.mathsisfun.com/data/standard-deviation.html

OpenStudy (anonymous):

2.23 -2 2 1 -2.44 ?

OpenStudy (amistre64):

not sqrt, squares

OpenStudy (amistre64):

25 16 16 1 36

OpenStudy (anonymous):

-_- pardon my stupidity. So now I add em up and divide by 5 right?

OpenStudy (amistre64):

variance is calcualted as the average of the squared differences from the mean. sum of [x-mean]^2 divided by the number of datapoints yes, add them up and divide by 5

OpenStudy (anonymous):

18.8

OpenStudy (amistre64):

yep

OpenStudy (amistre64):

X = (Xi........ mean.........Xf) subtract the mean from the set of X X-mean = (Xi-mean........ 0.........Xf-mean) we have zeroed the set, square the differences from the mean and take their average

OpenStudy (amistre64):

if we do this by hand, the sooner we can get the set near its zeroed mark, the simpler the calculations will be.

OpenStudy (amistre64):

otherwise, stick them in the stats calculator and hit a button :)

OpenStudy (amistre64):

as an aside, spose we got it down to this: 6 -3 5 2 -5 the mean is 5/5 = 1 we would subtract 1 from the set, and then square add average

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