Question

True or False: x2-16x+64/x-8 has no remainder.

Answer 1

@zepdrix ?

Answer 2

Is there anything x could be replaced by in the problem?

Answer 3

long division or synthetic division ?
which one you want to do ?

Answer 4

oh by the way it's x squared

Answer 5

or to find the remainder
solve divisor x -8 for x
and then plug x value into the equation x^2 -16x +64 you will get the answer

Answer 6

x-8=0
solve this for x

Answer 7

@zepdrix

Answer 8

You've got a whole bunch of good options that were suggested here :)

`Polynomial Long Division` and see if you end up with any remainder.
`Synthetic Division with x=8` and see if you end up with any remainder.
`Factor the Numerator` and see if it cancels out with anything in the denominator.
`Remainder Theorem` lets you plug x=8 into the numerator and see if you end up with anything other than 0.

Bunch of good options :O
Still confused?
Gotta try something ggiirrrrl!

Answer 9

so its true then

Answer 10

@zepdrix

Answer 11

Maybe 0_o
what makes you say that? lol
I think yer just guessing ;)

Answer 12

because isn't the part where it says x-8 means that is has no remainder

Answer 13

www.tiger-algebra.com/drill/((x~2-16x_64)/(x~2-9))=((x~2.../(x-8))/
((x2-16x+64)/(x2-9))=((x2-3x)/(x-8)). No solutions found ... Step 2 : x2 - 3x Simplify ——————— x - 8 ... Quotient : 1. Remainder : 5 ..... As this is a polynomial of an even degree it may not even have any real (as opposed to imaginary) roots ...

Answer 14

.