Question

Function help? Middle line? I don't understand the graph?

Answer 1

The middle line is the line where half of the function is above it and half of the function is below it.

Answer 2

secondly wolfram alpha is interpreting your function incorrectly

Answer 3

it should really be a vector field

Answer 4

wolfram can't teach you how to fly

Answer 5

http://www.wolframalpha.com/input/?i=5sec%283x+-+1%29

Set different values of n and see if that changes the midline

Answer 6

my advice to you is to play with all the numbers on the trig function then remember what numbers change what

Answer 7

In the link from wolframalpha I set n=1

Answer 8

@Australopithecus Looks like it's 2, is that true?

Answer 9

no it is not right, if you have a mac I recommend using the grapher program it comes with it is super useful

Answer 10

notice how the function changes as the numbers change

Answer 11

Hope this helps

Answer 12

@Australopithecus Sorry I still don't follow

Answer 13

For sec(x) wherei s the midline?

Answer 14

Here is a graph of sec(x)

Answer 15

middle line sorry

Answer 16

what is the middle line for sec(x)?

Please answer soon dont have much time left

Answer 17

If you dont know that is fine but I need to know

Answer 18

@Australopithecus its on 1

Answer 19

does 50% of the function seem to below and 50% above that line?

Answer 20

does 50% of the function seem to below the line and 50% of the function appear to above that line?

Answer 21

"seem to be"
sorry tired

Answer 22

@Australopithecus Below, it seems like

Answer 23

I dont think you understand what I mean. I am talking about symmetry. One second I will give you examples

Answer 24

for sin(x) the middle line would be

Answer 25

it would be y=0 because 50% of the function is above y=0 and 50% of the function is below y=0

Answer 26

for sin(x) + 3

the middle line would be y = 3

Answer 27

Notice that the only thing that changes the middle lines placement is the addition or subtraction of numbers from the trig function

Answer 28

so sec(x) would have the same middle line as 5sec(5x + n)

Answer 29

do you follow, it is alright if you do not dont get discouraged

Answer 30

just let me know and I can try to explain it again

Answer 31

@Australopithecus Wait so if the middle line is 1 isn't my answer just B?

Answer 32

the middle line for sec(x) is not 1

Answer 33

it is not symmetrical

Answer 34

http://en.wikipedia.org/wiki/Symmetry

http://upload.wikimedia.org/wikipedia/commons/thumb/f/f8/Asymmetric_%28PSF%29.svg/180px-Asymmetric_%28PSF%29.svg.png

Answer 35

just say you had a circle

Answer 36

You can draw a line of symmetry

Answer 37

If you drew a line away from the line of symmetry you would have an asymmetric line, if you folded at the line I drew it would not over lap

Answer 38

It is the same deal for the middle line

Answer 39

a line at y=1 is not symmetric

Answer 40

for sec(x)

Answer 41

A middle line for csc(x) would be this:

Answer 42

I recommend if you still arent getting this to take a break and come back to it

Answer 43

sometimes concepts take some time to sink in

Answer 44

dont get discouraged I have complete faith you can do this