Particle in a infinite potential well, which has a width of L. \[ E\psi (x)=\left[\frac{-\hbar ^2}{2m}\frac{d^2}{dx^2}+V(x)\right]\psi (x)\\ \psi _n (x)=\sqrt{\frac{2}{L}}\sin\left(\frac{\pi n x}{L}\right)\\ E_n=\frac{n^2\pi^2\hbar ^2}{2mL^2} \] The question is, what is the momentum of this particle?
I don't know whether it is valid to apply the momentum operator in this case. If I apply the momentum operator to the wavefunction, I get:\[ \begin{align*} &\hspace{1.5em}\mathbf{p}\psi_n(x)\\ &=-i\hbar\frac{d}{dx}\psi_n(x)\\ &=-ih\sqrt{\frac{2}{L}}\frac{\pi n}{L}\cos\left(\frac{\pi n x}{L}\right) \end{align*} \] Clearly you cannot have a imaginary momentum! Something must have gone wrong.
we can find the expection value of the momentum, or its value on the state represented by your wave function. Now that value is given by the subsequent formula: \[\Large p = \left\langle {{\psi ^*}} \right|\hat p\left| \psi \right\rangle = \int_0^L {{\psi ^*}} \left( { - i\hbar \frac{{d\psi }}{{dx}}} \right)dx\] I assumed that your problem is described by the subsequent drawing: |dw:1431430870763:dw|
I suggest to write your wave function as follows: \[\Large \begin{gathered} \psi \left( x \right) = A\left\{ {\exp \left( {i\Omega x} \right) - \exp \left( { - i\Omega x} \right)} \right\} = \hfill \\ \hfill \\ = 2iA\sin \left( {\Omega x} \right),\quad \left( {\Omega = \sqrt {\frac{{2mE}}{{{\hbar ^2}}}} } \right) \hfill \\ \end{gathered} \]
The drawing is correct. Is \(\Large p = \left\langle {{\psi ^*}} \right|\hat p\left| \psi \right\rangle\) the expectation value or the the momentum of the state? Furthermore, won't \(\hspace{1.5em} \Large\int_0^L {{\psi ^*}} \left( { - i\hbar \frac{{d\psi }}{{dx}}} \right)dx\\ \Large=\int_0^L\sqrt{\frac{2}{L}}\sin\left(\frac{\pi n x}{L}\right)\left(-ih\sqrt{\frac{2}{L}}\frac{\pi n}{L}\cos\left(\frac{\pi n x}{L}\right)\right)dx\) still be imaginary? One of the multiple choice question in my high school examination paper, which I finished a few days ago, asks for the the momentum of which a particle in a infinite potential well cannot have. However, I read somewhere that the momentum is not quantised for a particle in a infinite potential well. So I am trying to derive the momentum of a particle in a potential well and learn basic quantum mechanics on the way. Grateful if you could give me some advice.
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